Question

What is the point-slope form
The slope-intercept form of the equation of a:line that passes through point (-3, 8) is y=-2/3x+6
of the equation for this line?
y-3= -(x + 8)
y+3=_?(x-8)
y+8=-{(x-3)
y-8=-={(x + 3)

Answer 1

Answer:

$y-8=-\frac{2}{3}(x+3)$

Step-by-step explanation:

The point-slope from is: $y-y_{1}=m(x-x_{1})$

When:

M is the slope

x1 and y1 are the ordered pair.

The question gives us a equation of the line in slope intercept form: $y=mx+b$

When:

M is the slope

B is the y-intercept.

We can use the equation $y=-\frac{2}{3}x+6$ to determine the slope.

-2/3 replaces m, so that is the value of the slope.

We can now use the slope and the points to create the point slope equation.

m= -2/3

x1, y1 = (-3,8)

Plug in the information:

$y-8=-\frac{2}{3}(x+3)$