Respuesta :

Answer:

All of these

Explanation:

In MnO:

mass of Mn = 55 g (as 1 mole of Mn weighs 55 g)

mass of O = 16 g    (as 1 mole of O weighs 16 g)

The mass percent of metal Mn= [tex]\frac{55}{55+16}\times100=\frac{55}{71}\times100=77.46[/tex]

In MnO2:

mass of Mn = 55 g

mass of O = 2*16 = 32 g

The mass percent of metal Mn=[tex]\frac{55}{87}\times100=63.22[/tex]

In Mn2O3:

mass of Mn = 2*55 = 110 g

mass of O = 3*16 = 48 g

The mass percent of metal Mn=[tex]\frac{110}{158}\times100=69.62[/tex]

In all the cases the mass percent of metal is greater than 50.

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