Question

answer to 4(x-3)+5x-^2 for x=2

Answer 1

Answer:

Given expression $4(x-3)+5x^{\bf -2}$ for x=2  is

$4(x-3)+5x^{\bf -2}=-\frac{\bf 11}{\bf 4}$

Step-by-step explanation:

Given expression is  $4(x-3)+5x^{-2}$ for x=2

Let f(x) be the given expression

$f(x)=4(x-3)+5x^{-2}$

now to find f(x) for x=2

ie., put x=2 in f(x) we get

$4(x-3)+5x^{-2}=4(2-3)+5(2)^{-2}$

$4(x-3)+5x^{-2}=4(-1)+5(2)^{-2}$

$4(x-3)+5x^{-2}=-4+5\times \frac{1}{2}^}2}$

$4(x-3)+5x^{-2}=-4+5\times \frac{1}{4}$

$4(x-3)+5x^{-2}=-4+ \frac{5}{4}$

$4(x-3)+5x^{-2}= \frac{-16+5}{4}$

$4(x-3)+5x^{-2}= \frac{-11}{4}$

$4(x-3)+5x^{-2}=-\frac{11}{4}$

Therefore the given expression $4(x-3)+5x^{-2}$ for x=2  is

$4(x-3)+5x^{-2}=-\frac{11}{4}$