Answer:
[tex]\theta=156.81^{\circ}[/tex]
Explanation:
It is given that,
Force due to rope 1, [tex]F_x=700\ N[/tex]
Force due to rope 2, [tex]F_y=300\ N[/tex]
Let [tex]\theta[/tex] is the angle must a third rope tension be applied in order to keep the boat at rest. It can be given by :
[tex]tan\theta=\dfrac{F_y}{F_x}[/tex]
[tex]tan\theta=\dfrac{300}{700}[/tex]
[tex]\theta=23.19^{\circ}[/tex]
The angle clockwise from the positive x-axis will be equal to,
[tex]\theta=180-23.19[/tex]
[tex]\theta=156.81^{\circ}[/tex]
So, the angle must a third rope tension be applied in order to keep the boat at rest is 156.81 degrees. Hence, this is the required solution.