Two ropes apply a force to a boat. The first is 700 N in the positive x direction and 300 N in the positive y direction. In At what angle (clockwise from the positive x-axis) must a third rope tension be applied in order to keep the boat at rest?

Respuesta :

Answer:

[tex]\theta=156.81^{\circ}[/tex]

Explanation:

It is given that,

Force due to rope 1, [tex]F_x=700\ N[/tex]

Force due to rope 2, [tex]F_y=300\ N[/tex]

Let [tex]\theta[/tex] is the angle must a third rope tension be applied in order to keep the boat at rest. It can be given by :

[tex]tan\theta=\dfrac{F_y}{F_x}[/tex]

[tex]tan\theta=\dfrac{300}{700}[/tex]

[tex]\theta=23.19^{\circ}[/tex]

The angle clockwise from the positive x-axis will be equal to,

[tex]\theta=180-23.19[/tex]

[tex]\theta=156.81^{\circ}[/tex]

So, the angle must a third rope tension be applied in order to keep the boat at rest is 156.81 degrees. Hence, this is the required solution.

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