Respuesta :
Question is not proper, Proper question is given below.
There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels, there are 3 dimes. For every 2 dimes, there are 5 quarters. There are 500 coins in all. How many nickels, dimes, and quarters are in the piggy bank? How much are the coins in the piggy bank worth all together?
Answer:
There are 80 nickels, 120 dimes and 300 quarters in the piggy bank.
The piggy bank is worth $91.
Step-by-step explanation:
Let Number of Nickels be represented by 'n'.
Let Number of Dimes be represented by 'd'.
Let of Quarters be represented by 'q'.
Now Given:
For every 2 nickels, there are 3 dimes.
2 n = 3 d
1 n = number of dimes.
We will use Unitary method to find the same.
Number of 1 dimes d = [tex]\frac{3}{2}n[/tex]
Also Given:
For every 2 dimes, there are 5 quarters.
2 d = 5 q
1 d = number of quarters
We will use Unitary method to find the same.
Number of 1 quarter q = [tex]\frac{5}{2}d[/tex]
Also Given:
Total Number of coins = 500
[tex]n+d+q=500[/tex]
Now d = [tex]\frac{3}{2}n[/tex]
AND q = [tex]\frac{5}{2}d = \frac{5}{2} \times\frac{3}{2}n = \frac{15}{4}n [/tex]
So Substituting the values we get;
[tex]n+\frac{3}{2}n+\frac{15}{4}n=500[/tex]
Taking LCM we get making denominator as 4.
[tex]\frac{4}{4}n+\frac{3\times2}{2\times 2}n+\frac{15\times 1}{4\times 1}n=500\\\\\frac{4}{4}n+\frac{6}{4}n+\frac{15}{4}n=500\\\\\frac{4n+6n+15n}{4}=500\\\\\frac{25n}4 =500\\\\25n = 500\times 4\\\\25n =2000\\\\n=\frac{2000}{25}=80[/tex]
Hence number of Nickels n = 80
Number of Dimes d = [tex]\frac{3}{2}n=\frac{3}{2} \times 80 = 120[/tex]
Number of Quarters q = [tex]\frac{15}{4}n= \frac{15}{4} \times 80 = 300[/tex]
Hence There are 80 nickels, 120 dimes and 300 quarters in the piggy bank.
Now we know that;
1 nickel = $0.05
so 80 nickels = [tex]0.05\times80= $4[/tex]
1 dime = $0.1
so 120 dimes = [tex]0.1\times120= $12[/tex]
1 quarter = $0.25
so 300 quarters = [tex]0.25\times300= $75[/tex]
So Total money = $4+$12+$75 = $91
Hence the piggy bank is worth $91.