Question

The line above goes through points (-4,0) and (0,3). What is the equation of the line?

Answer 1

The equation of line going through points (-4, 0) and (0, 3) is $y = \frac{3}{4}x + 3$

Solution:

Given that line above goes through points (-4,0) and (0,3)

To find: equation of line

The equation of line passing through two points $(x_1 , y_1)$ and $(x_2, y_2)$ is given as:

$y - y_1 = m(x - x_1)$

Where "m" is the slope of line

The slope of line is given as:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Here for the given points (-4, 0) and (0, 3) we have:

$x_1 = -4 ; y_1 = 0 ; x_2 = 0 ; y_2 = 3$

Substituting the given values in slope formula,

$m=\frac{3-0}{0-(-4)}=\frac{3}{4}$

Thus slope of line $m = \frac{3}{4}$

Now substitute "m" into equation of line

Thus the required equation of line is:

$y - y_1 = m(x - x_1)\\\\y - 0 = \frac{3}{4}(x - (-4))\\\\y = \frac{3}{4}(x + 4)\\\\y = \frac{3}{4}x + 3$

Thus the required equation of line is found