Answer:
A. [tex]f(n)=4(4)^{n}[/tex]
Step-by-step explanation:
The geometric sequence has the form:
[tex]f(n)=ar^{n-1}[/tex]
where r=4 is the common ratio and [tex]a=16[/tex] is the first term.
When we plug in these values we obtain:
[tex]f(n)=16(4)^{n-1}[/tex]
We can use properties of exponents to simplify further to get:
[tex]f(n)=16\frac{(4)^{n}}{4^1}[/tex]
This gives us:
[tex]f(n)=4(4)^{n}[/tex]
The correct answer is A.