Answer:
19.3 L
Explanation:
Initially, Helium gas occupies a volume V₁ = 20.9 L at a temperature T₁ = 13°C = 286 K. Then, it occupies a volume V₂ at a temperature T₂ = -9°C = 264 K. We can find the new volume using Charles' law (assuming constant pressure and ideal gas behavior).
[tex]\frac{V_{1}}{T_{1}} =\frac{V_{2}}{T_{2}} \\\frac{20.9L}{286K} =\frac{V_{2}}{264 K} \\V_{2} = 19.3L[/tex]