To solve this problem it is necessary to apply the concepts related to momentum, momentum and Force. Mathematically the Impulse can be described as
[tex]I = F*t[/tex]
Where,
F= Force
t= time
At the same time the moment can be described as a function of mass and velocity, that is
[tex]P = m\Delta v \rightarrow P=m(v_1-v_2)[/tex]
Where,
m = mass
v = Velocity
From equilibrium the impulse is equal to the momentum, therefore
[tex]I = p[/tex]
[tex]Ft = m(v_1-v_2)[/tex]
PART A) Since the body ends at rest, we have the final speed is zero, so the momentum would be
[tex]p=m(v_1-v_2)[/tex]
[tex]p = 75*0.15[/tex]
[tex]p = 1125Kg\cdot m/s[/tex]
Therefore the magnitude of the person's impulse is 1125Kg.m/s
PART B) From the equation obtained previously we have that the Force would be:
[tex]Ft = m(v_1-v_2)[/tex]
[tex]F(0.025)= 1125[/tex]
[tex]F= 45000N[/tex]
Therefore the magnitude of the average force the airbag exerts on the person is 45000N