Which of the following choices has the compounds correctly arranged in order of increasing solubility in water? (least soluble to most soluble) A) CCl4< CHCl3< NaNO3 B) CH3OH < CH4< LiF C) CH4< NaNO3< CHCl3 D) LiF < NaNO3< CHCl3 E) CH3OH < Cl2< CHCl3

Respuesta :

Answer:

A) CCl4< CHCl3< NaNO3

Explanation:

answer is A

CCl4 is non polar and consequently has a very low solubility in water

CHCl3 is polar and soluble in water via London dispersion and dipole-dipole interaction  forces.

NaNO3 is an ionic compound and more soluble in water (ion-dipole interactions)

Note: A) CCl4< CHCl3< NaNO3

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