Respuesta :
Answer:
Keeping the speed fixed and decreasing the radius by a factor of 4
Explanation:
A ball is whirled on the end of a string in a horizontal circle of radius R at constant speed v. The centripetal acceleration is given by :
[tex]a=\dfrac{v^2}{R}[/tex]
We need to find how the "centripetal acceleration of the ball can be increased by a factor of 4"
It can be done by keeping the speed fixed and decreasing the radius by a factor of 4 such that,
R' = R/4
New centripetal acceleration will be,
[tex]a'=\dfrac{v^2}{R'}[/tex]
[tex]a'=\dfrac{v^2}{R/4}[/tex]
[tex]a'=4\times \dfrac{v^2}{R}[/tex]
[tex]a'=4\times a[/tex]
So, the centripetal acceleration of the ball can be increased by a factor of 4.
The centripetal acceleration of the ball can be increased by a factor of 4 by keeping the speed fixed and decreasing the radius by a factor of 4.
What is Centripetal acceleration?
Centripetal acceleration is the inward acceleration of an object moving in a circular path. The magnitude of centripetal acceleration can be obtained using the following formulas;
a = v²/r
where;
- v is the speed
- r is the radius of the circular path
When the speed is constant, centripetal acceleration can be increased by reducing the radius of the circle.
v² = ar
a₁r₁ = a₂r₂
r₂ = a₁r₁/a₂
when the acceleration is increased by a factor of 4
r₂ = (a₁r₁)/(4a₁)
r₂ = r₁/4
Thus, the centripetal acceleration of the ball can be increased by a factor of 4 by keeping the speed fixed and decreasing the radius by a factor of 4.
Learn more about centripetal acceleration here: https://brainly.com/question/79801