Question

what is the value of X? (8y+12) (7x+4)​

Answer 1

Answer:

The value of x is $-\frac{4}{7}$

Step by step explanation:

In the question we are given a product that contains two unknown variables, i.e. $x$ and $y$. To solve for $x$ we shall first compute the product between the two brackets. I will show each step in full detail, in order to understand the product computation of such cases (i.e. distributive property).

$(8y+12)(7x+4)=0\\\\8y*7x+4*8y+12*7x+12*4=0\\\\56xy+32y+84x+48=0$

Up to this point we have computed the product and now we have all our terms. Since we want to find the value of $x$ we will gather together all terms that contain $x$ (even if they also contain $y$) and then do some manipulations and simplifications to obtain our result, as follow:

$56xy+32y+84x+48=0\\\\56xy+84x=-32y-48\\\\14x(4y+6)=-8(4y+6)$

Now we see that on both sides of the equality we have a common term of   $(4y+6)$, which we can cancel out from both sides, which leaves us with:

$14x=-8\\\\x=-\frac{8}{14}\\\\ x=-\frac{4}{7}$

Thus the value of $x$ is $-\frac{4}{7}$.

Answer 2

Answer:

X=8

Step-by-step explanation:

I'm a little late, but perhaps somebody with the same question can be helped down the line.

ΔRST = Equilateral Triangle.

All 3 sides are equal in length, and all 3 angles are 60°.

7x + 4 = 60 (Subtract 4 from both sides)

7x = 56 (Divide both sides by 7)

x = 8 is your answer. (Credit to jimgrant1 for helping me originally.)