Question

x2 + 4y2 = 36
The length of the minor axis is:

Answer 1

Answer:

$length\ of \ minor\ axis = 6$

Step-by-step explanation:

Given:

The given equation is.

$x^{2} +4y^{2} =36$ -------------(1)

We write standard equation of an ellipse

$\frac{x^{2}}{a^{2}}+\frac{y^{2} }{b^{2} } = 1$-------(2)

So equation 1 divided by 36 for standard form of an equation

$\frac{x^{2}}{36}+\frac{4y^{2} }{36} = \frac{36}{36}$

$\frac{x^{2}}{36}+\frac{y^{2} }{9} = 1$

So we compare equation 1 and equation 2.

we get $a^{2} =36$ and $b^{2} =9$

so $a =6$ and $b =3$

The length of the minor axis is $2\times b$

Here $b=3$.

$length\ of \ minor\ axis = 2\times 3$

$length\ of \ minor\ axis = 6$

Therefore the length of the minor axis is 6