Question

Ax = 44.4 m and Ay = 25.1 m
Find the magnitude of the
vector.

Answer 1

Answer:

The magnitude of the vector A is 51 m.

Explanation:

Given:

The horizontal component of a vector A is given as:

$A_x=44.4\ m$

The vertical component of a vector A is given as:

$A_y=25.1\ m$

Now, we know that, a vector A can be resolved into two mutually perpendicular components; one along the x axis and the other along the y axis. The magnitude of the vector A can be written as the square root of the sum of the squares of each component.

Therefore, the magnitude of vector A is given as:

$|\overrightarrow A|=\sqrt{A_{x}^2+A_{y}^2}$

Now, plug in 44.4 for $A_x$, 25.1 for $A_y$ and solve for the magnitude of A. This gives,

$|\overrightarrow A|=\sqrt{(44.4)^2+(25.1)^2}\\|\overrightarrow A|=\sqrt{1971.36+630.01}\\|\overrightarrow A|=\sqrt{2601.37}\\|\overrightarrow A|=51\ m$

Therefore, the magnitude of the vector A is 51 m.