Question

NEED ANSWER

Two photographers at an aviation show are located 52 yards apart and take a picture of a helicopter in the sky at the same time. If their angles of elevation to the helicopter are 48° and 35°, what is the altitude of the helicopter rounded to the nearest hundredth?

Answer 1

Answer: the height of the helicopter is 22.33 yards

Step-by-step explanation:

The diagram illustrating the scenario is shown in the attached photo. A triangle, ABC is formed.

H represents the height of the helicopter.

x + y = 52

x = 52 - y

We would apply trigonometric ratio.

tan # = opposite side/adjacent side.

Tan 48 = H/x

H = xtan48

H = tan48×(52 - y)

H = 1.1106(52-y)

Also,

Tan 35 = H/y

H = ytan35

H = 0.7002×y

H = 0.7002y

Since H = H, therefore

1.1106(52-y) = 0.7002y

57.7512 - 1.1106y = 0.7002y

0.7002y + 1.1106y = 57.7512

1.8108y = 57.7512

y = 57.7512/1.8108

y = 31.89

Recall,

H = 0.7002y

H = 0.7002 × 31.89 = 22.33 yards