Question

Solve triangle ABC if A = 50°, a = 10, and b = 20. If no triangle exists, explain why.

Answer 1

Answer:

No triangle exist

Step-by-step explanation:

step 1

Find the measure of angle B

Applying the law of sines

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{10}{sin(50^o)}=\frac{20}{sin(B)}$

$sin(B)=20(sin(50^o))/10$

$sin(B)=1.532$

Remember that

The maximum value of the sine is 1

therefore

No triangle exist

Answer 2

Answer:

No triangle exists

Step-by-step explanation:

Angle B=? -------  a/sin(A)= b/sin (B) ------- substitute the given values ------- 10/sin(50º)=20/sin(B) ------- sin(B)=20(sin(50º))/10 ------- sin(B)=1.532

But the max value of sines is 1, so that means that no triangle exists.