Answer:
The time taken by the satellite to orbit earth at its surface, t = 1.66 hr
Explanation:
Given data,
The velocity of the satellite, v = 15000 miles/hr
The distance of travel, d = 24901 miles,
It is equal to the circumference of earth,
So the time taken by the satellite to orbit earth at its surface,
v = d/t
t = d/v
Substituting the given values in the above equation,
t = 24901 / 15000
= 1.66 hr
Hence, the time taken by the satellite to orbit earth at its surface, t = 1.66 hr
