Respuesta :

Answer: [tex]12.26 m/s^{2}[/tex]

Explanation:

We have the following data:

[tex]F=92 N[/tex] is the force exerted on the troll

[tex]W=73.5 N[/tex] is the weight of the troll

Now, the weight is expressed as:

[tex]W=m.g[/tex] (1)

Where [tex]m[/tex] is the mass of the troll and [tex]g=9.8 m/s^{2}[/tex] is the acceleration due gravity

Isolating [tex]m[/tex]:

[tex]m=\frac{W}{g}[/tex] (2)

[tex]m=\frac{73.5 N}{9.8 m/s^{2}}[/tex] (3)

[tex]m=7.5 kg[/tex] (4) This is the mass of th troll

On the other hand, the exerted force is given by:

[tex]F=m.a[/tex] (5)

Where [tex]a[/tex] is the acceleration:

[tex]a=\frac{F}{m}[/tex] (6)

[tex]a=\frac{92 N}{7.5 kg}[/tex] (7)

Finally:

[tex]a=12.26 m/s^{2}[/tex] This is the acceleration of the troll

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