help me solve # 15 & 16
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Answer:
15) [tex] C=frac{5}{9}(F-32)[/tex]
16) 12 hours
Step-by-step explanation:
15) [tex]F=\frac{9}{5}C+32 \\F-32 = \frac{9}{5}C\\\frac{5}{9}(F-32)=C[/tex]
16) If Jim drove 168 mi in 4 hours, this means it takes him
[tex] \frac{4 hours }{168 mi} [/tex]
this many hours to drive 1 mile. So if we multiply this by 504 mi:
[tex] \frac{4 hours }{168 mi} 504 mi = 4 \cdot 3 hours = 12 hours [/tex]