Question

8. Create a Punnett square to solve the following monohybrid cross Patty is homozycous dominant for freckles (55),
while Charlie is homozygous for no freckles (ss).
a. What is the genotype of the potential offspring?
b. What is the probability their children having no freckles?

Answer 1

Answer:

A Punnett square for the following monohybrid cross can be shown as follows:

         s         s

S      Ss      Ss

S      Ss     Ss

a) The genotype of the potential offspring will be Ss, they will be heterozygous dominant.

b) There is a zero% probability that the offspring will have no freckles.  As one of the parents was homozygous dominant for the freckles, hence all of the offsprings will have freckles.