Question

There are six times as many whitetail deer as mule deer in the woods. If Jacob gets one deer in the woods? What is the probability that Jacob gets a mule deer?

Answer 1

Answer:

C) The probability that Jacob gets a mule deer is 1/7.

Step-by-step explanation:

Let us assume the number of mule deer in the woods  = m

So, the number of whitetail deer  = 6 x ( Number of mule deer) = 6 (m) = 6 m

Also, the total number of deer = Mule deer + whitetail deer

                                                    =  m + 6 m = 7 m

Let E: Event of Picking a mule deer in the woods.

$\textrm{P(E)}  = \frac{\textrm{Number of favorable observations}}{\textrm{ Total number of observations }}$

So, here $\textrm{P(Picking a mule deer )}  = \frac{\textrm{Number of Mule deers in the woods}}{\textrm{ Total number of deer }}  = \frac{m}{7m}  = \frac{1}{7}$

or, P(E) = 1/7

Hence, the  probability that Jacob gets a mule deer is 1/7.

Answer 2

Answer:

C) The probability that Jacob gets a mule deer is 1/7.

Step-by-step explanation:

Let us assume the number of mule deer in the woods  = m

So, the number of whitetail deer  = 6 x ( Number of mule deer) = 6 (m) = 6 m

Also, the total number of deer = Mule deer + whitetail deer

                                                   =  m + 6 m = 7 m

Let E: Event of Picking a mule deer in the woods.

So, here

or, P(E) = 1/7

Hence, the  probability that Jacob gets a mule deer is 1/7.