For which discriminant is the graph possible
b2-4ac=0
b2-4ac=-1
b2-4ac=4
![For which discriminant is the graph possible b24ac0 b24ac1 b24ac4 class=](https://us-static.z-dn.net/files/d03/a540e9d52f24f3a13295c6a41eb0c43e.png)
Answer:
The graph is possible for [tex]b^2-4ac=4[/tex]
Step-by-step explanation:
we know that
The discriminant of a quadratic equation of the form
[tex]ax^{2} +bx+c=0[/tex]
is equal to
[tex]D=b^2-4ac[/tex]
If D=0 the quadratic equation has only one real solution
If D>0 the quadratic equation has two real solutions
If D<0 the quadratic equation has no real solution (complex solutions)
In this problem , looking at the graph, the quadratic equation has two real solutions (the solutions are the x-intercepts)
so
[tex]b^2-4ac > 0[/tex]
therefore
The graph is possible for [tex]b^2-4ac=4[/tex]