Question

When responding to sound, the human eardrum vibrates about its equilibrium position. Suppose an eardrum is vibrating with an amplitude of 5.70 10-7 m and a maximum speed of 2.66 10-3 m/s. (a) What is the frequency (in Hz) of the eardrum's vibration

Answer 1

Answer:

Frequency will be 743.09 Hz

Explanation:

We have given maximum speed $v_m=2.66\times 10^{-3}m/sec$

Amplitude $A=5.7\times 10^{-7}m$

We have to find the frequency of the vibration

We know that angular frequency is given by

$\omega =\frac{v_m}{A}=\frac{2.66\times 10^{-3}}{5.7\times 10^{-7}}=4666.666rad/sec$

$2\pi f=4666.66$

$f=743.09Hz$