Question

How many x-intercepts appear on the graph of this polynomial function?
1 Rx)= x -x + x²-x
1 x-intercept
2 x-intercepts
3 x-intercepts
4 x-intercepts

Answer 1

Answer:

The given function$R(x) = x - x + x^2  - x$ has 2 x -intercepts.

Step-by-step explanation:

Here, the given polynomial function is :

$R(x) = x - x + x^2  - x\\\implies R(x) = x^2 - x$

or,  $y  = x^2 - x$ ............  (1)

X- intercept is the point in the graph of R(x), where the coordinate y = 0.

Now, substituting the value of y  =  0 in (1) find all x - intercepts:

$y  =  0   \implies x^2 - x = 0\\x(x-1)  =0\\\implies(x-0)(x-1) = 0$

⇒ Either x = 0 ,         or x - 1 = 0 ⇒  x = 1

⇒The given function has two x intercepts at x  = 0 and x = +1

Hence, the given function$R(x) = x - x + x^2  - x$ has 2 x -intercepts.

Answer 2

Answer:

2 x-intercepts on edge2020

Step-by-step explanation: