The player will get 10 hits for 15 times strikes out.
The player will strike out 69 times for 46 hits.
Step-by-step explanation:
Given,
Ratio of strike out to hits = 3:2
Condition 1: If the player gets 15 strikes out;
Let,
x be the hits for 15 times strikes out.
Using proportion;
Strike out : hit :: strike out : hit
[tex]3:2::15:x[/tex]
Product of mean = Product of extreme
[tex]15*2=3*x\\3x=30[/tex]
Dividing both sides by 3;
[tex]\frac{3x}{3}=\frac{30}{3}\\x=10[/tex]
The player will get 10 hits for 15 times strikes out.
Condition 2: if the player gets 46 hits
Let,
y be the strikes out.
Using proportion,
Strike out : hit :: strike out : hit
[tex]3:2::y:46[/tex]
Product of mean = Product of extreme
[tex]2*y=46*3\\2y=138[/tex]
Dividing both sides by 2;
[tex]\frac{2y}{2}=\frac{138}{2}\\y=69[/tex]
The player will strike out 69 times for 46 hits.
Keywords: Ratio, proportion
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