Question

mitchell and his lab partner were conducting a titration experiment. their goal was to neutralize 0.50 mol naoh. how many moles of h2so4 are needed to complete the neutralization?

Answer 1

Answer: The amount of sulfuric acid needed to complete the neutralization is 0.25 moles

Explanation:

We are given:

Moles of NaOH = 0.50 moles

The chemical equation for the reaction of NaOH and sulfuric acid follows:

$2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O$

By Stoichiometry of the reaction:

2 moles of NaOH reacts with 1 mole of sulfuric acid

So, 0.50 moles of NaOH will react with = $\frac{1}{2}\times 0.50=0.25$ moles of sulfuric acid

Hence, the amount of sulfuric acid needed to complete the neutralization is 0.25 moles