Question

Find the differential for P=0.2x^(2)-17x-10

Answer 1

The differential for P = 0.2x² -17x -10 is P' = 0.4x - 17

Step-by-step explanation:

Let us revise how to differentiate an equation with respect to x

If the equation is $y = ax^{n}+b$ , where a , b are constant

• The differentiation of the term $ax^{n}$ is $a(n)x^{(n-1)}$ (multiply the coefficient of x by the power"n" and subtract 1 from the power)
• The differentiation of the term b is 0, because b is a constant
• The differentiation of y is $\frac{dy}{dx}=a(n)x^{(n-1)}+0=a(n)x^{(n-1)}$
• You can write $\frac{dy}{dx}$ as y'

∵ P = 0.2x² - 17x - 10

- Let us differentiate each term

∵ The differentiation of 0.2x² is $0.2(2)x^{2-1}=0.4x^{1}=0.4x$

∵ The differentiation of -17x is $-17(1)x^{1-1}=-17x^{0}=-17(1)=-17$

∵ The differentiation of -10 is zero because the differentiation

    of the numerical term is 0

∴ The differentiation of P is P' = 0.4x - 17

The differential for P = 0.2x² -17x -10 is P' = 0.4x - 17

Learn more:

You can learn more about the differentiation in brainly.com/question/4279146

#LearnwithBrainly