Given sin 60 degrees = square root of 3 divided by 2 , find cos 60 degrees.

Answer:
cos60° = [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
Using the trigonometric identity
sin²x + cos²x = 1 ⇒ cos x = [tex]\sqrt{1-sin^2x}[/tex]
Given
sin60° = [tex]\frac{\sqrt{3} }{2}[/tex], then
cos60° = [tex]\sqrt{1-(\frac{\sqrt{3} }{2})^2 }[/tex] = [tex]\sqrt{1-\frac{3}{4} }[/tex] = [tex]\sqrt{\frac{1}{4} }[/tex] = [tex]\frac{1}{2}[/tex]