Respuesta :

Answer:

The correct answer is -

option A)

Step-by-step explanation:

It is given that the maximum of the wave is 100 units

For option A)

F(t) would be maximum when cos([tex]\dfrac{2π}{5}[/tex]t) = -1

∴ [tex]F(t)_{max}[/tex] = 60 - 40(-1) = 60 + 40 = 100

Similarly we get ,

[tex]F(t)_{max}[/tex]  = 100 for all other options.

Also It is given that minimum of the wave is 20 units.

For option a)

Minimum of F(t) occurs when

cos([tex]\dfrac{2π}{5}[/tex]t) = 1

∴ [tex]F(t)_{min}[/tex] = 60 - 40 = 20.

However for option B) and D) , in a similar manner -

[tex]F(t)_{min}[/tex] = - 60

But for option C)

[tex]F(t)_{min}[/tex] =  60 + 40(-1) = 20.

Hence we discard option b) and d).

Given that the time period of the cycle is 5 ms

We know that Time period of wave is given by -

T = [tex]\frac{2π}{ω}[/tex] , where ω = angular frequency of the wave.

∴ [tex]\frac{2π}{ω}[/tex] = 5.

∴ ω = [tex]\frac{2π}{5}[/tex].

For option c)

ω = 5.

But for option a)

ω = [tex]\frac{2π}{5}[/tex].

∵ option a) satisfies all the given conditions ,

The correct answer is option a).

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