Question

3x +10 < 3 or 2x -5 > 5

Answer 1

For this case we must find the solution set of the given inequalities:

Inequality 1:

$3x + 10 <3$

Subtracting 10 from both sides of the inequality:

$3x <3-10$

Different signs are subtracted and the major sign is placed.

$3x <-7$

We divide between 3 on both sides of the inequality:

$x <- \frac {7} {3}$

The solution is given by all values of x less than$- \frac {7} {3}$

Inequality 2:

$2x-5> 5$

Adding 5 to both sides of the inequality:

$2x> 5 + 5\\2x> 10$

Dividing by 2 to both sides of the inequality:

$x> \frac {10} {2}\\x> 5$

The solution is given by all values of x greater than 5.

Thus, the solution set is given by:

(-∞, $- \frac {7} {3}$) U (5,∞)

ANswer:

(-∞, $- \frac {7} {3}$) U (5,∞)