Respuesta :
Answer:
[tex](a+b)^n ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + ..... +{n \choose n}a^{(0)}b^{(n)}[/tex]
Step-by-step explanation:
The Given question is INCOMPLETE as the statements are not provided.
Now, let us try and solve the given expression here:
The given expression is: [tex](a +b)^n, n > 0[/tex]
Now, the BINOMIAL EXPANSION is the expansion which describes the algebraic expansion of powers of a binomial.
Here, [tex](a+b)^n = \sum_{k=0}^{n}{n \choose k}a^{(n-k)}b^{(k)}[/tex]
or, on simplification, the terms of the expansion are:
[tex](a+b)^n ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + ..... +{n \choose n}a^{(0)}b^{(n)}[/tex]
The above statement holds for each n > 0
Hence, the complete expansion for the given expression is given as above.