Answer:
the linear size of the smallest box in which you can confine an electron
=7 μm
Explanation:
From the uncertainity principle we can write that
[tex]\Delta p\Delta x = \frac{h}{4\pi}[/tex]
x= position of electron
p= momentum of electron
h= planks constant
[tex]\Delta x= \frac{h}{2\pi\times2m\Delta v}[/tex]
here the moving of electron will taken two times
as the electrons are going and reflected from the wall of the box
so the velocity Δv= 2*13= 26 m/s
now putting the values of all the variables in the above equation
[tex]\Delta x= \frac{6.625\times10^{-34}}{2\pi\times2(9.1\times10^{-31})26}[/tex]
⇒Δx= 7×10^{-6} m
=7 μm