What is the output of the following code? var x = ["a", "b", "c"]; x.push("d", "e"); x.pop(); x.pop(); a. x = ["a", "b", "d", "e"] b. x = ["d", "e"] c. x = ["a", "b", "c"] d. x = ["c", "d", "e"]

The stack is part of the data structure. In this stack perform two operations that are "push and pop". The push function is used to push(insert) and pop function is used to pop(delete) elements on the stack. It follows the LIFO process that stands for last in first out.

In this code, firstly we insert three elements on the stack that is "a, b and c".
Then, we insert two elements on the stack that is "d and e", in this element store in the upper part of the stack and then we call pop function two times.
In first time, the call will remove elements e and the second time it will remove element d.

That's why the answer is option "C".

What is the output of the following code? var x = ["a", "b", "c"]; x.push("d", "e"); x.pop(); x.pop(); a. ​x = ["a", "b", "d", "e"] b. ​x = ["d", "e"] c. ​x = ["a", "b", "c"] d. ​x = ["c", "d", "e"]

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What is the output of the following code? var x = ["a", "b", "c"]; x.push("d", "e"); x.pop(); x.pop(); a. x = ["a", "b", "d", "e"] b. x = ["d", "e"] c. x = ["a", "b", "c"] d. x = ["c", "d", "e"]