Answer:
The lengths of the sides of a right triangle are
Longer leg = 0.4 units.
Shorter leg = 0.3 units.
Step-by-step explanation:
Given:
Hypotenuse = 0.5 units
Let the length of shorter leg of right triangle be x units then
According to the given condition,
length of longer leg will be (0.1 + x) units
Now,we know for a right triangle,by Pythagoras theorem we have
[tex](\textrm{Hypotenuse})^{2} = (\textrm{Longer leg})^{2}+(\textrm{Shorter leg})^{2}[/tex]
substituting the values we get
[tex]0.5^{2}= (x+0.1)^{2}+ x^{2}[/tex]
Applying [tex](a+b)^{2}= a^{2}+2ab+b^{2}[/tex] we get
[tex]0.25= x^{2} +2\times 0.1\times x+ 0.1^{2} + x^{2} \\2x^{2} +0.2x+0.01-0.25=0\\2x^{2} +0.2x-0.24=0\\[/tex]
which is a quadratic equation
dividing the equation throughout by two we get
[tex]x^{2} +0.1x-0.12=0\\\textrm{on factorizing we get}\\x^{2} +0.4x-0.3x-0.12=0\\(x+0.4)(x-0.3)=0[/tex]
[tex]\therefore (x-0.3)= 0\\\therefore x=0.3[/tex]
Since x cannot be negative we take
x = 0.3 units
∴ Longer leg = x + 0.1
= 0.3+0.1
=0.4 units
So, the lengths of the sides of a right triangle are
Longer leg = 0.4 units.
Shorter leg = 0.3 units.
