Question

A rigid stainless steel chamber contains 140 Torr of methane, CH4, and excess oxygen, O2, at 160.0 °C. A spark is ignited inside the chamber, completely combusting the methane. What is the change in total pressure within the chamber following the reaction? Assume a constant temperature throughout the process.

Answer 1

Answer:

The variation of pressure is 0.

Explanation:

Methane combustion reaction:

$CH_4 + 2 O_2 \longrightarrow CO_2 + 2 H_2O$

The pressure change in gaseous state reactions at constant T y V is proportional to the change in the number of mol of gas in total.

As can be seen in the reaction above we have 3 moles of gas in the reactants and 3 in the products, so the variation of moles is 0. Therefore, the variation of pressure is also 0.