Answer:
7.30523 m/s
Explanation:
t = Time taken
u = Initial velocity = 0
v = Final velocity
s = Displacement = 2.72 m
g = Acceleration due to gravity = 9.81 m/s² = a
Equation of motion
[tex]v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 2.72+0^2}\\\Rightarrow v=7.30523\ m/s[/tex]
The speed which a quarter would have reached before contact with the ground is 7.30523 m/s