Question

Identify the precipitate or lack thereof for the following:CaCl2(aq) + K2CO3(aq) --> CaCO3 + 2KClA) CaCO3B) KClC) No precipitateFeCl2(aq) + (NH4)2SO4(aq) --> FeSO4 + 2NH4ClA) FeSO4B) NH4ClC) No precipitate

Answer 1

Answer:

A) CaCO₃

C) No precipitate

Explanation:

To answer these questions we need to consider the solubility rules.

Identify the precipitate or lack thereof for the following:

CaCl₂(aq) + K₂CO₃(aq) ⇒ CaCO₃(s) + 2 KCl(aq)

• Group II carbonates are insoluble. Thus, CaCO₃ is insoluble.
• Salts containing Group I cations are soluble. Thus, KCl is soluble.

FeCl₂(aq) + (NH₄)₂SO₄(aq) ⇒ FeSO₄(aq) + 2 NH₄Cl(aq)

• Most sulfates are soluble. Thus, FeSO₄ is soluble.
• Salts containing the ammonium ion are soluble. Thus, NH₄Cl is soluble.