Question

The magnetic coils of a tokamak fusion reactor are in the shape of a toroid having an inner radius of 0.700 m and an outer radius of 1.30 m. The toroid has 800 turns of large-diameter wire, each of which carries a current of 17.0 kA. (a) Find the magnitude of the magnetic field inside the toroid along the inner radius. T (b) Find the magnitude of the magnetic field inside the toroid along the outer radius. T

Answer 1

To solve this problem it is necessary to apply the concepts related to Magnetic field in a toroide.

By definition the magnetic field is defined as

$B = \frac{\mu_0 NI}{2\pi r}$

Where,

$\mu_0 =$ Permeability constant in free Space

N = Number of loops

I = Current

r = Radius

PART A) For the internal radio,

$B = \frac{4\pi*10^{-7}(800)(17*10^3)}{2\pi 0.7}$

$B = 3.8857T$

PART B) For outside radio,

$B = \frac{4\pi*10^{-7}(800)(17*10^3)}{2\pi *1.3}$

$B = 2.0923T$

Answer 2

Answer:

(a) 3.886 tesla  

(b) 2.09 tesla

Explanation:

inner radius, r = 0.7 m

outer radius, R = 1.3 m

current, i = 17 kA = 17000 A

Number of turns, N = 800

(a) The magnetic field is given by

$B=\frac{\mu _{0}}{2\pi }\times N\times \frac{i}{r}$

$B=\frac{2 \times 10^{-7}\times 800 \times 17000}{0.7}$

B = 3.886 tesla

(b) The magnetic field is given by

$B=\frac{\mu _{0}}{2\pi }\times N\times \frac{i}{R}$

$B=\frac{2 \times 10^{-7}\times 800 \times 17000}{1.3}$

B = 2.09 tesla