Question

Suppose that a student is randomly selected from a large high school. The probability that the student is a senior is 0.22. The probability that the student has a driver’s license is 0.30. The probability that the student is a senior or has a driver’s license is 0.36. What is the probability that the student is a senior and has a driver’s license?

Answer 1

Answer: Our required probability is 0.16.

Step-by-step explanation:

Since we have given that

Probability that the student is a senior = 0.22

Probability that the student has a driver license = 0.30

Probability that the student is a senior or has a driver's license = 0.36

We need to find the probability that the student is a senior and has a driver's license.

According to question,

$P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\\P(S\cap D)=0.22+0.30-0.36\\\\P(S\cap D)=0.16$

Hence, our required probability is 0.16.

Answer 2

Answer:

The probability that the student is a senior AND has a driver's license is $P(S\cap D)=0.16$.

Step-by-step explanation:

Given information:

The probability that the student is a senior is $P(S)=0.22$.

The probability that the student has a driver’s license is $P(D)=0.30$.

The probability that the student is a senior OR has a driver’s license is $P(S\cup D)=0.36$.

So, the probability that the student is a senior and has a driver’s license will be,

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\0.36=0.22+0.30-P(S\cap D)\\P(S\cap D)=0.16$

Therefore, the probability that the student is a senior and has a driver's license is $P(S\cap D)=0.16$.

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https://brainly.com/question/17089724?referrer=searchResults