Question

The International Space Station is equipped with a Vika Oxygen Generator which uses the following reaction to generate oxygen. LiClO subscript 4 space (s )space rightwards arrow LiCl space (s )space plus space 2 space straight O subscript 2 space (g )Determine the mass (in Kg) of LiClO4 required to fill the 9.3x105 L interior volume of the International Space station with oxygen at a pressure of 0.22 atm and a temperature of 22.2 ˚C. You may find the following molecular weights useful: LiClO4 - 106.39 g/mol LiCl - 42.394 g/mol O2 - 31.9998 g/mol Report your answer below. Do not use scientific notation, or include units. If Carmen adds zeros behind the decimal place in your answer, do not worry. Your response will be graded correctly.

Answer 1

Answer:

440

Explanation:

Let's consider the following reaction for the production of O₂.

LiClO₄(s) → LiCl(s) + 2 O₂(g)

First, we have to calculate the moles of O₂ using the ideal gas equation.

$P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{0.22atm\times 9.3\times 10^{5}L}{(0.082atm.L/mol.K)\times 295.4K} =8.4 \times 10^{3} mol$

Then, we can establish the following relations:

• 2 moles of O₂ are produced per mole of LiClO₄.
• The molar mass of LiClO₄ is 106.39 g/mol.
• 1 kg = 10³ g

The mass of LiClO₄ that produced 8.4 × 10³ moles of O₂ is:

$8.4 \times 10^{3} molO_{2}.\frac{1molLiClO_{4}}{2molO_{2}} .\frac{106.39 \times 10^{-3} kgLiClO_{4}}{1molLiClO_{4}} =4.4 \times 10^{2} kgLiClO_{4}$

Answer 2

The mass of LiClO4 required is 449.55 Kg.

Equation of the reaction;

LiClO4 (s)→ LiCl(s) + 2 O2(g)

We have the following information about the of gas evolved;

P =  0.22 atm

V = 9.3x105 L

T =  22.2 ˚C + 273 = 295.2 K

Where;

PV = nRT

R = 0.082 atmLK-1mol-1

n = PV/RT

n =  0.22 atm × 9.3 x 10^5 L/ 0.082 atmLK-1mol-1 ×  295.2 K

n = 8451 moles

Since 1 mole of LiClO4 produces 2 moles of oxygen

x moles of LiClO4  produces  8451 moles of oxygen

x =  1 mole × 8451 moles/2 moles

x = 4225.5 moles

Molar mass of LiClO4 = 106.39 g/mol

Mass of LiClO4 = 106.39 g/mol × 4225.5 moles = 449.55 Kg

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