Answer:
[tex]C_{mix} = 45.833 mg/l[/tex]
Explanation:
Give data:
flow rate of stream is [tex]Q_1 100 cfs[/tex]
concentration of suspended solids [tex]SS_1 5 mg/L[/tex]
During spring time,
concentration of TSS = [tex]SS_2 = 250 mg/l[/tex]
flow rate of stream [tex]Q_2= 20 cfs[/tex]
we know that, concentration of mix is given as
[tex]C_{mix} = \frac{Q_1 SS_1 + Q_2 SS_2}{Q_1 +Q_2}[/tex]
[tex]C_{mix} = \frac{100\times 5 + 20\times 250}{100+20}[/tex]
[tex]C_{mix} = 45.833 mg/l[/tex]