Question

At an amusement​ park, guests have to take either a train or a boat 14 miles from the parking lot to the front entrance and then back when they leave the park. The train goes 10 mph faster than the boat. Abdul takes the train into the park and the boat on his way back. The boat goes an average speed of 20 mph. How long did the round trip​ take?

Answer 1

Answer:

$\frac{7}{6} hours$

Step-by-step explanation:

Distance for one way = 14 miles

The boat goes an average speed of 20 mph

The train goes 10 mph faster than the boat.

Speed of train = 20+10 = 30 kmph

Abdul takes the train into the park and the boat on his way back.

Time taken for going into park by train = $\frac{Distance}{\text{Speed of train}}$

                                                                 = $\frac{14}{30}$

Time taken for going back by boat = $\frac{Distance}{\text{Speed of train}}$

                                                                 = $\frac{14}{20}$

So, total time =  $\frac{14}{30}+\frac{14}{20}=\frac{7}{6} hours$

Hence the round trip​ take $\frac{7}{6} hours$

Answer 2

The period of the round trip is mathematically given as

T=7/6hours

What is the period of the round trip?

Question Parameter(s):

guests have to take either a train or a boat 14 miles

The train goes 10 mph faster than the boat.

The boat goes an average speed of 20 mph.

Generally, the equation for the time   is mathematically given as

t=d/v

Therefore

For going fort

t=14/30

For going back

t'= 14/20

In conclusion, total time

$T= \frac{14}{30}+\frac{14}{20}$

T=7/6

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