Answer:
9/49
Step-by-step explanation:
For the first die, probability of obtaining 4= 2/7
For the second die, the probability of obtaining 3= 2/7
Other outcomes for each die appear with a probability of 1/7
There are six cases of obtaining the sum of the two die as 7.
E1 = 1 and 6
E2 = 2 and 5
E3 = 3 and 4
E4 = 4 and 3
E5 = 5 and 2
E6 = 6 and 1
Pr(E1) = 1/7*1/7
= 1/49
Pr(E2) = 1/7*1/7
= 1/49
Pr(E3) = 1/7*1/7
= 1/49
Pr(E4) = 2/7*2/7
= 4/49
Pr(E5) = 1/7*1/7
= 1/49
Pr(E6)= 1/7*1/7
= 1/49
P(E) = Pr(E1) + Pr(E2) + Pr(E3) + Pr(E4) + Pr(E5) + Pr(E6)
= 1/49 + 1/49 + 1/49 + 4/49 + 1/49 + 1/49
= 9/49
