An empty parallel plate capacitor is connected between the terminals of a 4.4-V battery and charged up. The capacitor is then disconnected from the battery, and the spacing between the capacitor plates is quadrupled. As a result of this change, what is the new voltage between the plates of the capacitor?
I have:E = v/dE =9 Vthen the distance is doubled 9(2) = 18 V
