Answer:
Step-by-step explanation:
We have the area of a circle
[tex]A_O=81\pi[/tex]
The sector with a central angle of
[tex]120^o[/tex]
Calculate, what part of 360° is an angle 120°:
[tex]\dfrac{120^o}{360^o}=\dfrac{1}{3}[/tex]
The same part of an area of a circle is an area of a segment.
Therefore:
[tex]A_S=\dfrac{1}{3}\cdot81\pi=27\pi[/tex]
Use π ≈ 3.14
[tex]A_S\approx(27)(3.14)=84.78[/tex]