Answer:
The company manufactures 5 Delta cars, 8 Beta cars and 12 Sigma cars.
Step-by-step explanation:
Let in the motor company x number of Delta cars, y number of Beta cars and z number of Sigma cars are manufactured.
So, from the condition given in the question we can write
9x + 13y + 9z = 257 ........ (1)
4x + 6y + 4z = 116 ........... (2) and
3x + 4y + z = 59 ......... (3)
From equation (2) we get
9x + 13.5y + 9z = 261 ....... (4) {Multiplying with [tex]\frac{9}{4}[/tex] both sides}
Now, solving equations (1) and (4) we get
0.5y = 4
⇒ y = 8.
Now, from equation (2) putting the value of y we get,
4x + 4z = 116 - 48 = 68
⇒x + z = 17 .......... (5)
Now, from equation (3) putting y = 8 we get,
3x + z = 59 - 32 = 27 ........ (6)
Hence, solving equations (5) and (6) we get, 17 - x = 27 - 3x
⇒ 2x = 10
⇒ x = 5
So, z = 17 - x = 12
Therefore, the company manufactures 5 Delta cars, 8 Beta cars and 12 Sigma cars. (Answer)