Answer:0.829 to 0.853
Explanation:
Given
height through ball is dropped [tex]h=254 cm[/tex]
velocity at just before collision is [tex]u=\sqrt{2gh}[/tex]
[tex]u=\sqrt{2\time 9.8\times 2.54}[/tex]
[tex]u=7.05 m/s[/tex]
if the now if the ball rises to a height of 175 cm , velocity after collision to reach at that height is
[tex]v_a=\sqrt{2\times 9.8\times 1.75}=5.85 m/s[/tex]
if the ball rises to an height of 185 cm then velocity after collision
[tex]v_b=\sqrt{2\times 9.8\times 1.85}=6.02 m/s[/tex]
value of e for [tex]h=175 cm[/tex]
[tex]e=\frac{5.85}{7.05}[/tex]
[tex]e=0.829[/tex]
e for 185 cm
[tex]e=\frac{6.02}{7.05}=0.853[/tex]
Range of e is 0.829 to 0.853