Answer:
A. Ionic radius, Na⁺ is to small.
Explanation:
The channel pore contains a narrow selective filter that is delimited by carbonyl oxygens (C = O) of the polypeptide skeleton. When a K⁺ ion enters the selection filter it interacts with these carbonyl oxygens, and the water molecules to which the K⁺ was attached move, allowing the dehydrated K⁺ to pass through the pore. However, a dehydrated Na⁺ is too small to interact with these carbonyl oxygens in the selective filter, which is kept open. As a consequence, this hydrated sodium ion is too large to pass through the canal.