Answer:
[tex]y=(x-4)(x-2)[/tex]
Step-by-step explanation:
Consider the given equation
[tex]y=x^2-6x+8[/tex]
Factor form of a parabola: It displays the x-intercepts.
[tex]y=a(x-p)(x-q)[/tex] .... (1)
where, a is a constant and, p and q are x-intercepts.
So, we need to find the factored form of the given equation.
Splinting the middle term we get
[tex]y=x^2-4x-2x+8[/tex]
[tex]y=x(x-4)-2(x-4)[/tex]
[tex]y=(x-4)(x-2)[/tex] .... (2)
On comparing (1) and (2) we get
[tex]p=4,q=2[/tex]
It means x-intercepts of the given parabola are 4 and 2.
Therefore, equivalent forms of the equation is y=(x-4)(x-2).