Question

Please help with that problem
Important İ have quiz tomorrow

Answer 1

Answer:

Final pressure of the gas remaining in the first container is 3.5 atm

Explanation:

Since it is given that temperature is constant , we can apply -

PV=constant , where

P = Pressure of the gas

V = Volume of the container in which the gas is contained

Initially,

For container 1 -

$P_{i}$ = 4 atm

$V_{1}$ = 6 L

Finally,

For container 2 -

$P_{f,2}$ = 3 atm

$V_{2}$ = 1 L

For container 1 -

$P_{f,1}$ = ?

$V_{1}$ = 6 L

∴ $P_{i}$$V_{1}$ = $P_{f,1}$$V_{1}$ + $P_{f,2}$$V_{2}$

∴ 4×6 =  ($P_{f,1}$×6) +(3×1)

∴ $P_{f,1}$ = 3.5 atm